In Cl_2O_{6(l)} + HF to P + Q. If H of acid H | vedclass

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(B) The reaction is $Cl_2O_6 + HF 	o [ClO_2]^+[ClO_4]^- + HF 	o [ClO_2]^+ + [ClO_4]^-$. Given that $H$ of $HF$ attaches to $Q$,$Q$ must be the $[ClO

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$Q: sp^3; 109^\circ 28'$

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(B) The reaction is $Cl_2O_6 + HF 	o [ClO_2]^+[ClO_4]^- + HF 	o [ClO_2]^+ + [ClO_4]^-$. Given that $H$ of $HF$ attaches to $Q$,$Q$ must be the $[ClO_4]^-$ ion,making $P$ the $[ClO_2]^+$ ion. For $P$ $([ClO_2]^+)$: The $Cl$ atom is $sp^2$ hybridized with one lone pair,resulting in a bent shape with $\angle OClO For $Q$ $([ClO_4]^-)$: The $Cl$ atom is $sp^3$ hybridized with a tetrahedral geometry,resulting in $\angle OClO = 109^\circ 28'$. Comparing with the given options,$B$ is the correct statement regarding $Q$.

In $Cl_2O_{6(l)} + HF \to P + Q$. If $H$ of acid $HF$ attaches with $Q$,then identify the correct option for hybridization of $Cl$ atom and $\angle OClO$ in the $P$ and $Q$ ions.

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